I need help again sorry-

f(x) = - 2(x - 3)² + 2

Step-by-step explanation:

Given

f(x) = - 2x² + 12x - 16 ( factor out - 2 from the first 2 terms )

      = - 2(x² - 6x) - 16

To complete the square

add/subtract ( half the coefficient of the x- term)² to x² - 6x

f(x) = - 2(x² + 2(- 3)x + 9 - 9) - 16

     = - 2(x - 3)² + 18 - 16

     = - 2(x - 3)² + 2

cube of any positive integer is of the form 9m,9m+1 or 9m+8. In this question, why do we take a=3q, a=3q+1 and a=3q+2. why cant we take a=2q and a=2q+1. or a=5q, 5q+1, 5q+2, 5q+3 and 5q+4. why do we specifically use a=3q and 3q+1 if a is any positive integer and can be represented in other ways?

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