Use the circle with a center (7.-9) and passing through D (-2,3). Which of the following is an equation of the line tangent to the circle and passing through point D?
A y + 9 = $(x - 7)
B
c
D
y - 3 = }(x + 2)
y+9 = }(x - 7)
y-3 = (x + 2)
y+9= -(x - 2)
y-3= -(x + 2)
E
F
G
y+9=--(x - 7)
I

D because it’s Tristian

Step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.