The current altitude of the plane is 15400 feet above the ground and the plane's horizontal distance to the airport is 200000 miles away. What angle of depression must the pilot make on his descent in order to safely land on the runway>

0.441°

Step-by-step explanation:

tan = 1540/200000

tan = 0.0077

tan-1(0.0077) = 0.441

angle of depression is 0.0441°

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.