Which quadratic equation has 2 and -3 as its roots ?

alfa = 2

beeta = -3

product of zeros = 2x-3= -6

sum of zeros = 2+[-3] = -1

POLYNIMIAL = k[x²-[sum]+product]

                       =k[ x²-[-1] +[-6]]

                        = k[ x²+1 -6]

                        = x²-5

hence , the quadratic equation is x²-5

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∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

y=mx+b

step-by-step explanation:

m slope

b y-intercept