What are the zeros of the function f(x) = x^2 + 5x + 5 written in simplest radical form?

2x = -5 +/- root 5 (opt 3)

Step-by-step explanation:

0 = 4f(x)

 = 4(x^2 + 5x + 5)

 = 4x^2 + 20x + 20

 = (2x)^2 + 2*2x+5 + 25 - 5

 = (2x + 5)^2 - (root 5)^2

 = ((2x+5) - 5) ((2x + 5) + 5)

 = (2x + 5 - 5) (2x + 5 - 5)

Therefore, 2x = -5 +/- root 5

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answer: it's d

step-by-step explanation: