Suppose the heights of men in a particular country have a normal distribution with a mean of 70 inches and a standard deviation of 3 inche a) What percentage of men would have a height between 66 and 75 inches? Give answer to the nearest whole percent.
b) If a random group of 350 men in this country were measured, how many of them would we expect to be between 66 and 75 inches?
c) Below what height would we expect 2.5% of all men to be?
d)What would it mean if someone's height is 3 standard deviations from the mean?

simplifying

7ln(x + 2.8) = 11.2

reorder the terms:

7ln(2.8 + x) = 11.2

(2.8 * 7ln + x * 7ln) = 11.2

(19.6ln + 7lnx) = 11.2

solving

19.6ln + 7lnx = 11.2

solving for variable 'l'.

move all terms containing l to the left, all other terms to the right.

reorder the terms:

-11.2 + 19.6ln + 7lnx = 11.2 + -11.2

combine like terms: 11.2 + -11.2 = 0.0

-11.2 + 19.6ln + 7lnx = 0.0

the solution to this equation could not be determined.

step-by-step explanation:

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