A journal article reports that a sample of size was used as a basis for calculating a CI for the true average natural frequency (Hz) of delaminated beams of a certain type. The resulting interval was . You decide that a confidence level of is more appropriate than the level used. What are the limits of the interval

The limit of the (228.533, 234.735)

Step-by-step explanation:

The values are missing in the given question. Therefore, in order to attempt this question, we will make assumptions.

So, let's assume that:

sample size of the journal article that was reported = 5

which is applied for determining a 95% CI

Also, assuming that the resulting interval = (229.764, 233.504)

However, if we are to use a 99% CI which we deemed to be more appropriate;

Then, our objective is to find the limits of this particular interval in question.

To do that:

We need to first find the sample mean at 95% CI by using the formula:

Since; df = n - 1

df = 5 - 1

df = 4

Then;

Sample mean = 231.634

Using the same formula to determine the standard deviation, we have:

At t = 0.025 and df = 4; = 2.776

s = 1.5063

The 99% CI is:

At t =0.005 and df =4; = 4.604

the required function is .

step-by-step explanation:

from the given table it is noticed that the graph passing through (-3,7), (0,4), (3,1) and (8,-4).

it is a linear function because the value of y is decrease by one as the value of x increase by 1.

the slope of the function is

the slope of the function is -1 and the y-intercept is 4.

the slope intercept form is

where, m is slope and b is y-intercept.

therefore the required function is . the graph of this function is shown below.