The diagram shows a cubeAh=11.3cn correct to the nearest millimetre calculate the lower bound for the length of an edge of the cub you must show all your working

Lower bound for the length of the edge = 42.5 cm

Step-by-step explanation:

From the picture attached,

FH is the diagonal of square EFGH.

Therefore, length of diagonal FH =

(By applying Pythagoras theorem)

In triangle AFH,

AH² = AF² + FH²

       = AF² +

       = AF² + FG² + HG²

AH² = 3HG²

(11.3)² = 3(HG²)

HG =

HG = 42.563 cm

For distance correct to the nearest mm, lower bound for the length of the edge = 42.5 cm

And upper bound for the length of the edge = 43.6 cm

use google you idiot omg you're so annoying

step-by-step explanation: