H(-4), h(0), h(4), h(8)
h(x)= {-(x+1)^2 + 7, x<2
{ -1/3x, x>4
h(-4)=
...
Mathematics, 25.05.2021 19:50 scholar13
H(-4), h(0), h(4), h(8)
h(x)= {-(x+1)^2 + 7, x<2
{ -1/3x, x>4
h(-4)=
h(0)=
h(4)=
h(8)=
PLEASE HELP
Answers: 3
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