The difference between two numbers is 7. The sum of three times the larger number and twice the smaller number is 16. Drag and drop the correct options from the list menu to make each statement below true.

28 and 12 . (QUORA)

Step-by-step explanation:

Let’s write this down. We are looking for X and Y.

The difference between two numbers is 16: −=16

Three times the larger number is seven times the smaller:  ∗3=∗7

So, we need to solve X and Y from these two equations.

If we re-arrange X*3 = Y*7, we get Y = X*3/7.

So, −∗3/7=16 .  −∗3/7  is the same as  7∗/7−3∗/7 , or  4∗/7 . So  4∗/7=16−>4∗=7∗16−>=7∗4=28 .

Then we just go back to  −=16 , and  =28 , gives us  28−=16,  or  =28–16−>=12 .

So the numbers are 28 and 12.

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