Consider the relation R defined on a set A = {0, 1, 2, 3, 4, 5} as follows: R = {(0,0), (0,1), (0,2), (0,4), (1,3), (1,5), (1,4), (2,0), (2,2), (2,3), (2,5), (3,0), (3,1), (3,2), (3,3), (4,1), (4,2), (4,4), (4,5), (5,1), (5,2), (5,4), (5,5)} (a) Is R reflexive? Justify your answer.
(b) Is R symmetric? Justify your answer.
(c) Is R transitive? Justify your answer.

its a

Step-by-step explanation:

answer;

the correct answer

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{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1