M∠AOC=104 ∘
m, angle, A, O, C, equals, 104, degrees
\qquad m \angle AOB = 7x + 30^\circm∠AOB=7x+30
∘
m, angle, A, O, B, equals, 7, x, plus, 30, degrees
\qquad m \angle BOC = 9x + 42^\circm∠BOC=9x+42
∘
m, angle, B, O, C, equals, 9, x, plus, 42, degrees
Find m\angle BOCm∠BOCm, angle, B, O, C:

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%

Iam not good at math i wish i could