Given: sin'(A) = L -2v5.1 5
What is the value of cos(A-B)?
25
25
inlin
5
5
o 25
115
25

then, the surface area of the sphere shown in the image is: 256π sq. units!

step-by-step explanation:

the lateral surface area of a sphere is 2πrh where h=2r.

then:

surface area = 4πr^2.

in this case, r=8 units ⇒ surface area = 4π(8 units)^2. = 256π sq. units!

then, the surface area of the sphere shown in the image is: 256π sq. units!

- 70

this is the answer for you hope it

stops on an even number.

hard

step-by-step explanation: