David made a triangle with sides 6 cm, 9cm , 12 cm. George wanted to make a triangle bigger in size but similar to that drawn by David. If the length of small side is 10 cm, find the length of other sides of the triangle drawn by David.​

Step-by-step explanation:

Given :

\triangle ABC \sim \triangle XYZ .△ABC∼△XYZ.

AB = 6\:cm, \:BC = 9 \:cm, CA = 12 \:cmAB=6cm,BC=9cm,CA=12cm

Let \: XY = 10\:cm, \:YZ = x \:cm, \: XZ = y /:cmLetXY=10cm,YZ=xcm,XZ=y/:cm

\frac{AB}{XY} = \frac{BC}{x} = \frac{CA}{y}XYAB=xBC=yCA

\blue {( The \: lengths \:of \: corresponding }(

\blue {sides \:are \: proportional .)}sidesareproportional.)

\implies \frac{6}{10} = \frac{9}{x} = \frac{12}{y}⟹106=x9=y12

i) \implies \frac{6}{10} = \frac{9}{x}i)⟹106=x9

\implies x = \frac{9 \times 10}{6}⟹x=69×10

\implies x = 15\:cm⟹x=15cm

ii) \implies \frac{6}{10} = \frac{12}{y}ii)⟹106=y12

\implies y = \frac{12 \times 10}{6}⟹y=612×10

\implies y = 20\:cm⟹y=20cm

Therefore.,

\red { Value \:of \:x } \green { = 15\:cm }Valueofx=15cm

\red { Value \:of \:y } \green { = 20\:cm }Valueofy=20cm

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i am thinking c. sorry if im wrong .

step-by-step explanation: