A baseball player hit 67 home runs in a season. Of the 67 home runs, 21 went to right field, 25 went to right center field, 11 went to center field, 8 went to left center field, and 2 went to left field. What is the probability that a randomly selected home run was hit to right field?

21/67 will be the probability.

Step-by-step explanation:

Ok so the player hit 67 home runs. An there was 21 which was hit to right field, so it will be 21/67

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

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step-by-step explanation: