14x^2=8y^2-6xy where x>0 and y>0 find the ratio x:y​

4 : 7

Step-by-step explanation:

First, you can start by moving all the terms to one side:

14x^2 + 6xy - 8y^2 = 0

Now we can start to factor this equation in order to find the ratio. We can start by factoring out the GCF, which is 2:

2(7x^2 + 3xy - 4y^2) = 0

In order to factor this equation we multiply the coefficients in front of the x^2 and y^2 term to get: 7 * -4 or -28. We are looking for numbers that have a product of -28 and a sum of 3(as the coefficient of the xy term). These two numbers are 7 and -4. We can rewrite the equation as:

2(7x^2 + 7xy - 4xy - 4y^2) = 0

Now, we can start to factor by grouping:

2( 7x[x + y] - 4y[x + y] ) = 0

And we can factor out [x + y]:

2(x + y)(7x - 4y) = 0

So, we can use the zero product property to get two equations:

x + y = 0

and

7x - 4y = 0

You get:

x =  -y

and

7x = 4y

We can get cancel out the first solution because both x and y have to be positive. Rearranging the second equation we can get x : y = 4 : 7

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions