Jenny had 7 dimes and 3 pennies in her She takes a coin out from her pocket, looks at the coin and then replaces it her pocket before she removes a second coin. What is the probability she will not take out a penny both times?

F. 3/10

G. 9/100

H. 49/100

J. 21/100

Explanation:

There are 7 dimes and 3 pennies, leading to 7+3 = 10 coins total.

The probability of not picking a penny is 7/10. If the first coin is put back, then the probability doesn't change for the second selection.

The probability of getting two dimes is (7/10)*(7/10) = 49/100 when the first coin is replaced.

If the first coin is not replaced, then the answer would be (7/10)*(6/9) = 42/90 = 7/15

idk

step-by-step explanation:

answer: apothems is your answer

step-by-step explanation: hope u get it right