Mathematics, 22.05.2021 21:50 pearljammarow6ujs

A grocer has 2 kinds of tea, one that sells for $8.00 per pound and the other that sells for $6.00 per pound. How many pounds of each kind must he use to make 50 pounds of tea that will sell for $7.40 per pound? Answer in pounds of $8.00 tea and pounds of $6.00 tea
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Answer from: hntnhtthnyt

35 pounds of $8.00 tea and 15 pounds of $6.00 tea

Step-by-step explanation:

Let x represent the pounds of tea of the $8 kind. 8x would represent the total cost of that type of tea. We can also say 50 - x is the pounds of tea of the $6 kind, so 6(50 - x) is the total cost of that type of tea. 50 * 7.4 represents the total cost of all the tea, and the expression 8x + 6(50 -x) would also represent the same thing. We can write this as an equation,

8x + 6(50 -x) = 50 * 7.4

simplify,

8x + 300 - 6x = 370

2x + 300 = 370

and solve.

2x = 70

x = 35

This means there is 35 pounds of the $8 kind.

We can subtract that from 50 to find,

50 - 35 = 15,

15 pounds is the amount of the $6 kind.

Answer from: infoneetusinghoyg22o

amount of $8 tea = 35 lb

amount of $6 tea = 15 lb

Step-by-step explanation:

Let x = amount of $8 tea

Then 50 - x = amount of $6 tea

Total cost of $8 tea is = 8x

Total cost of $6 tea = 6(50 - x)

Total cost of $7.40 tea = 7.4(50)

Total cost of $8 tea + Total cost of $6 tea = Total cost of $7.40 tea

8x + 6(50 - x) = 7.4(50)

8x + 300 - 6x = 370

2x = 70

x = 35

50 - x = 15

Answer from: Quest

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step-by-step explanation:

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Answer from: Quest

the system of inequity is

$y\leq -x+4$

$3y> x$

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

the solid line passing through the points (0,4) and (4,0).

$y-4=\frac{0-4}{4-0}(x-0)$

$y=-x+4$

the related equation of solid line is $y=-x+4$ .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

$y-0=\frac{0-1}{3-0}(x-0)$

$3y=x$

the related equation of dashed line is $3y=x$

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

$1=-0+4$

$1=4$

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be $\leq$ . the required inequality is

$y\leq -x+4$

similarly, check the second related equation.

$3(1)=0$

it is a dashed line, so this statement is true if the sign of inequality is > . the required inequality is

$3y> x$

15 points write a system of inequalities to represent the shaded portion of the graph

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