If anyone's good with interquartile range, median, upper quartile, lower quartile stuff, please help ASAP!

B, Range is 16, IQR is 7

Step-by-step explanation:

Quartiles:

Quartiles mark each 25% of a set of data:

The first quartile Q1 is the 25th percentile

The second quartile Q2 is the 50th percentile

The third quartile Q3 is the 75th percentile

The second quartile Q2 is easy to find. It is the median of any data set and it divides an ordered data set into upper and lower halves. The first quartile Q1 is the median of the lower half not including the value of Q2. The third quartile Q3 is the median of the upper half not including the value of Q2.

How to Calculate Quartiles:

Order your data set from lowest to highest values

Find the median. This is the second quartile Q2.

At Q2 split the ordered data set into two halves.

The lower quartile Q1 is the median of the lower half of the data.

The upper quartile Q3 is the median of the upper half of the data.

If the size of the data set is odd, do not include the median when finding the first and third quartiles. If the size of the data set is even, the median is the average of the middle 2 values in the data set. Add those 2 values, and then divide by 2. The median splits the data set into lower and upper halves and is the value of the second quartile Q2.

How to Find Interquartile Range

The interquartile range IQR is the range in values from the first quartile Q1 to the third quartile Q3. Find the IQR by subtracting Q1 from Q3.

IQR = Q3 - Q1

How to Find the Minimum:

The minimum is the smallest value in a sample data set.

Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the minimum is the smallest value x1. The formula for minimum is:

Min=x1=min(xi)ni=1

How to Find the Maximum:

The maximum is the largest value in a sample data set.

Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the maximum is the largest value xn.

can you add an image ?

step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.