The school that DeShawn goes to is selling tickets to the annual dance competition. On the first day of ticket sales, the school sold 10 senior citizen tickets and 8 child tickets for a total of $252. The school took in $280 on the second day by selling 10 senior citizen tickets and 10 child tickets. What is the price each of one senior citizen ticket and one child ticket?

Both child tickets and senior tickets cost $14.

Step-by-step explanation:

Since the school that DeShawn goes to is selling tickets to the annual dance competition, and on the first day of ticket sales, the school sold 10 senior citizen tickets and 8 child tickets for a total of $ 252, while the school took in $ 280 on the second day by selling 10 senior citizen tickets and 10 child tickets, to determine what is the price of each of one senior citizen ticket and one child ticket, the following calculation must be performed:

10 senior tickets + 8 child tickets = 252

10 senior tickets + 10 child tickets = 280

280 - 252 = 2 child tickets

28 = 2 child tickets

28/2 = 1 child ticket

14 = 1 child ticket

14 x 10 = 140

(280 - 140) / 10 = senior tickets

140/10 = 14 = senior tickets

Therefore, both child tickets and senior tickets cost $14.

it has to have an angle of 90 degrees

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.