Show that (X+1)(x+3)(x+5) can be written in the form ax^3+bx^2+cx+d

(x+1)(x+3)(x+5) = x^3 + 9 x^2 + 23 x + 15

Step-by-step explanation:

If you apply the distributive property, you can expand the expression to x^3 + 9 x^2 + 23 x + 15, from that you can see that:

a = 1

b = 9

c = 23

d = 15

And with these values, ax^3+bx^2+cx+d completely equals the given expression.

answer: (1,3) and (-2,0) i think.

what?

step-by-step explanation: