Determine the lateral area and the surface area of a right rectangular prism that has rectangular bases measuring 2"x4" and a height of 8".​

112 in^2

Step-by-step explanation:

Given data

Length =2in

Width= 4in

Height=8 in

The expression for the total surface area is

SA=2lw+2lh+2hw

SA= 2*2*4+2*2*8+ 2* 4*8

SA= 16+ 32+ 64

SA= 112 in^2

Hence the surface area is 112 in^2

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

step-by-step explanation: