Which function's graph has x-intercepts at x=−1 and x=3, and a vertex at point (1,−4)?

I  not know this problem at all.

Step-by-step explanation:

Top right option: g(x) = (x-1)(x+3)

Step-by-step explanation:

x=-1 is the solution to x+1=0

x=3 is the solution to x-3=0

Therefore, your expression so far is (x+1)(x-3) or x²-2x-3.

Since the vertex must be (1,-4) we must check if x=1 satisfies the equation x=-b/2a:

x=-b/2a

1=-(-2)/2(1)

1=2/2

1=1

Both sides are equal to each other, so the final function is g(x) = (x-1)(x+3)

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

bn,mn,n.vn.

step-by-step explanation: