Randy took a standardized test that is normally distributed. He scored a 105 on the test. The nationwide mean score on the test was 94 and the standard deviation was 6.2. What percent of the tested population scored higher than Randy on the test? Round to the nearest whole percent.

4% of the tested population scored higher than Randy on the test

Step-by-step explanation:

P(X>105) = normalcdf(105,1e99,94,6.2) = 0.0380155219 ≈ 0.038 ≈ 3.8% ≈ 4%

Therefore, about 4% of the tested population scored higher than Randy on the test.

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