A state trooper records the highway speeds of 60 drivers on two different stretches of highway. Stretch 1: minimum-55, Q1-57.5, median-63, Q3-68, maximum-71. Stretch 2: Minimum-60, Q1-63, median-65, Q3-68 maximum-74 outlier-81. 1. What percent of drivers in stretch 1 went faster than 63 mph?
2. How many drivers were going faster than 68 in stretch 2?
3. What is the interquartile range for stretch 2?
4. Which stretch likely has a larger standard deviation?

  the correct choice is marked

step-by-step explanation:

the first two graphs show multiple turning points. the last graphs matches the description in every detail.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

you need to add a picture