A bag contains 6 white marbles, 5 red marbles, 19 marbles of other colors. Find the probability of choosing a white marble and then a red marble if you replace the first marble before choosing the second marble.

1/30

Step-by-step explanation:

      6 white marbles

      5 red marbles

+    19 marbles of other colors

     30 marbles in total

First drawing:

p(white) = (number of white marbles)/(total number of marbles)

p(white) = 6/30 = 1/5

Second drawing:

Since the first marble is replaced, there are still 30 marbles in the bag.

p(red) = (number of red marbles)/(total number of marbles)

p(red) = 5/30 = 1/6

The two drawings are independent events, so the overall probability of the two events is the product of the individual probabilities.

p(white then red) = p(white) × p(red)

p(white then red) = 1/5 × 1/6

p(white then red) = 1/30

93.8

step-by-step explanation:

lets say, first number = x

second number = 3x+7

total = 49

(x)+(3x+7)= 49

4x+7 = 49

4x = 42

x = 42/4

x= 10.5

x= 10.5

3x+7 = 3(10.5)+7 = 93.8

hope this