F the perimeters of each shape are equal, which equation can be used to find the value of x? A triangle with base x + 2, height x, and side length x + 4. A triangle with length of x + 3 and width of one-half x.
(x + 4) + x + (x + 2) = one-half x + (x + 3)
(x + 2) + x + (x + 4) = 2 (one-half x) + 2 (x + 3)
2 (x) + 2 (x + 2) = 2 (one-half x) + 2 (x + 3)
x + (x + 2) + (x + 4) = 2 (x + 3 and one-half)

(x + 2) + x + (x + 4) = 2 (one-half x) + 2 (x + 3)

Step-by-step explanation:

triangle base: x + 2, height x, and side length x + 4 - - - -

b = x + 2 ; a = x ; c = x + 4

Perimeter (P) of a triangle :

P = a + b + c

P =( x + 2) + x + (x + 4)  - (1)

Length of x + 3 with Width one haf X.

l = x + 3  w = 1/2 x

Perimeter of rectangle (P) = 2(l+w)

P =  2 ( x + 3 ) + 2 ( 1/2 x )

( Anwer)

(1) = (2)

(x + 2) + x + (x + 4) = 2(x+3) + 2(1/2x)

Hope it helps!

B

Step-by-step explanation:

happy to help

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