For what values of x is the expression below defined?
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x > 0

Step-by-step explanation:

Given :-

And we need to find the value of x for which the expression is defined . The expression is ,

√[3x²] ÷ √[4x]

As we can see that x is inside the squareroot. So for defining the expression the value of x should be Greater than 0 . As negative inside the squareroot will give rise to imaginary numbers.

Solution :-

x > 0

In interval notation :-

Therefore x should be Greater than 0 .

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

answer: 0.64

step-by-step explanation: