What are the zeroes of the function
nf(x) = x2 + 2x - 35?

x = - 7, x = 5

Step-by-step explanation:

To find the zeros, let f(x) = 0 , that is

x² + 2x - 35 = 0 ← in standard form

(x + 7)(x - 5) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 7 = 0 ⇒ x = - 7

x - 5 = 0 ⇒ x = 5

its 8

step-by-step explanation:

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3