Trangle ABC has vertices A (4, 1), B (1,9) and C (-5, - 2). The translation to create triangle A'B'C' is (x, y) + (x+1, y-1). Which of the following will be the coordinates of the vertices of triangle A'B'C?

I've been stuck on this for a minute
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x= 149. 24+7=31. 180-31=149

your welcome

answer: the answer is 5/22

step-by-step explanation: if you subtract 17 from 22 the answer is 5 therefore the remainder of students are female

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i