4. You randomly select three marbles from jar that contains 23 black
marbles, 32 blue marbles and 8 white marbles.
What is the probability that the first marble is blue, the second marble
is black and the last marble is not blue if you do not replace the first
and second marbles? Enter your answer as a decimal rounded to the
nearest thousandth.
Marble, blue marble first time, red marbles second time, white marble

0.093 chance

Step-by-step explanation:

23 black + 32 blue + 8 white = 63 total

FIRST MARBLE IS BLUE:

32/63

SECOND MARBLE IS BLACK:

23/62

LAST MARBLE IS NOT BLUE:

30/61

MATH:

32/63*23/62*31/61 = 0.093

sorry if it’s wrong but I think it’s right

.093

Step-by-step explanation:

There are 63 marbles in the jar

P(pick a blue) = 32/63

Since you are not replacing that marble, so there are 62 marbles in the jar, 31 blue, 23 black, 8 white

P(pick a black) = 23/62

Now there are 61 marbles in the jar. 22 black, 31 blue and 8 white

P(not a blue) = 30/61

P(blue, black, not blue) = (32/63)(23/62)(30/61)

                                      = .093

if you was gonna solve for a, a is a   < -12