2. The pointer of a spinner with 3 congruent sectors is spun once and a tetrahedron labelled 1 to 4 is rolled
R
1
The table shows the possible outcomes.
Tetrahedron
1
2
3
R
R/1
R/3
R/A
R/2
G/2
Spinner G
G/1
G/3
G/4
B/4
В B
B/1
B/2
B/3
Find the probability of cach cvent:
a) the pointer landing on red
P(red) = 12
HINI
Howy
Odlcomes erede
Flow may
outcomes have a 3
b) rolling a 3
P(3) = 1
12
c) red and a 3
P(R/3) =
Compare the probability in parte) with the product of the probabilities in parts a) and b).
What do you notice?​

step-by-step explanation:

consider an orange peel: if you want to try and lay it flat, you have to stretch it, we know exactly how things are being stretched or squashed at any given point. we have many different map projections because each has different patterns of some projections can even preserve certain features of the earth without

graph b

step-by-step explanation:

one solution- graph a (clear intercepting point.)

no solution- graph b (they're parallel, there will never be a point of interception.)

infinite solutions- graph c (all points intercept.)

point form: (-3,-1)

equation form: x=-3 y=-1

step-by-step explanation: