Quadrilateral ABCD is shown in the illustration. Prove that ABCD is a parallelogram with opposite sides that are congruent.
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△cde maps to △stu with the transformations (x, y) arrowright (x − 2, y − 2) arrowright (3x, 3y) arrowright (x, −y). if cd = a + 1, de = 2a − 1, st = 2b + 3 and tu = b + 6, find the values of a and b. the value of a is and the value of b is .

16 more than the product of 5 and p

What is the answer to this question? i'm a bit stumped. also how do i do it? 5(x - 4) = 2(x + 5)