A bag contains 6 white marblesw and 4 black marbles. a marble is drawn from the bag and then a second marble is drawn without replacing the first one. what is the probability of drawing a white marble on the first draw and another white marble on the second draw

60.5%

Step-by-step explanation:

60% white, 40% black

The first draw you have a 60% chance drawing a white marble, the second time you have a 55% chance since you already drew one in the first round. so i think it is 60.5%% chance drawing white on both rounds since I add 60+55=121. 121/200=60.5%

1/3

Step-by-step explanation:

answer: expected value of x = 1.0

step-by-step explanation:

p(x=0) = 0.25

p(x=1) = 0.50

p(x=2) = 0.25

expected value for x = 0×0.25 + 1×0.5 + 2×0.25 = 1.0