What are the coordinates of the vertices of D(3, A) (△ABC) for A(0, 4), B(–2, 5), and C(3, 7)? A. A′(0, 12), B′(−6, 15), C′(9, 21) B. A′(0, 15), B′(−6, 18), C′(9, 24) C. A′(0, 9), B′(−6, 12), C′(9, 18) D. A′(0, 4), B′(−6, 7), C′(9, 13)

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

tip $2.90

total $17.40

this is a good question! i'll do some research and come back when i have the answer!