Can someone please solve these?

Step-by-step explanation:

h = -6 +20t + 4

I will use calculus,  maybe that's not how you're supposed to do this

-12t +20 =0

12t = 20

t = 20 /12

t = 1

t = 1

there will be a max at  1.6666666666  seconds

-6*  + 20 * 1.6666666666  +4

= 16.666666666666 + 33.333333333333 + 4

= - 16 + 33 + 4

= 20  feet max height ( not too high,  for a rocket)

time of flight:

0 = -6 +20t + 4

use quadratic formula to find t

-20 +- sqrt [ - 4*(-6)*4 ] / 2*(-6)

-20 +- sqrt [400 + 96 ] / -12

-20 +- sqrt [496 ] / -12

-20 +- 22.27105 / -12

try the negative option 1st

-42.27105 / -12

3.522 seconds.     time of flight

when will the rocket be at 12' ? :

12 = -6 +20t + 4

0 = -6 +20t -8

use quadratic formula again to find t

-20 +- sqrt [ - 4*(-6)*(-8) ] / 2*(-6)

-20 +- sqrt [ 400 - 192 ] / -12

-20 +- sqrt [208 ] / -12

-20 - 14.4222 / -12

-34.4222 / -12

2.8685 seconds ( on the way down)

and

-20 + 14.4222 / -12

-5.578 / - 12

0.4648  seconds ( on the way up )

the answer is b

step-by-step explanation:

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !