In a survey of 802 U. S. adult drivers, 265 state that traffic is getting worse in their community. Construct a 95% confidence interval for the proportion of residents who think traffic is getting worse in their community.

The 95% confidence interval for the proportion of residents who think traffic is getting worse in their community is (0.2978, 0.3630).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the z-score that has a p-value of .

In a survey of 802 U.S. adult drivers, 265 state that traffic is getting worse in their community.

This means that

95% confidence level

So , z is the value of Z that has a p-value of , so .

The lower limit of this interval is:

The upper limit of this interval is:

The 95% confidence interval for the proportion of residents who think traffic is getting worse in their community is (0.2978, 0.3630).

idk this answer sorry cant on this one.

step-by-step explanation:

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it