Question 1 of 10 Jacob throws an acorn into the air. It lands in front of him. The acorn's path is
described by the equation y = -2x2 + 12x+8, where x is the acorn's horizontal
distance from him and y is the height of the acorn.
Solve - 2x2 + 12x + 8 = 0 to see where the acorn hits the ground.
Are both solutions reasonable in this situation?
A. x= -12 + J13 = -8.39 feet and x = -12 -v1-13-15.61 feet. Both
solutions are reasonable.
B. x = -12 + V13-8.39 feet and x = -12 -v1-13 -15.61 feet.
Distance can't be negative, so neither solution is reasonable.
O C. X = 3 + J13 * 6.61 feet and x = 3 - 313--0.61 feet. Both solutions
are reasonable
D. X = 3 + 13 = 6.61 feet and x = 3 - 13 - -0.61 feet. Distance can't
be negative, so x = 3 - 13 is not a reasonable solution