5. Find the Area (A = L x W) of a square that has a length measuring 3a²b²c1​

9a^4b^4c^2

Step-by-step explanation:

Area of a  square is expressed using the formula

A =L²

L is the side length of the square

Given that;

L = a²b²c

A = 3²(a²b²c)²

A = 9(a²)²(b²)²c²

A = 9a^4b^4c^2

Hence the area of the square is 9a^4b^4c^2

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72

it would open into a square depending on the type of envelope i’m not sure about the second part