Find the area of ABCD trapezoid ABCD ~ trapezoid EFGH
trapezoid ABCD: 20cm
trapezoid EFGH: 5cm

area of EFGH = 40 sq cm

640 cm²

Step-by-step explanation:

The ratio of the area of 2 similar polygons = the ratio of the square of their corresponding lengths

Thus:

Area of Trapezoid ABCD to Area of Trapezoid EFGH = AB² to EF²

Area of Trapezoid ABCD = ? = x

Area of Trapezoid EFGH = 40 cm²

AB = 20 cm

EF = 5 cm

Substitute

x:40 = 20²:5²

x/40 = 400/25

x/40 = 16

Cross multiply

x = 16*40

x = 640

Area of trapezoid ABCD = 640 cm²

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )