Brandon is an amateur marksman. When he takes aim at a particular target on the shooting range, there is a 0.10.10, point, 1 probability that he will hit it. One day, Brandon decides to attempt to hit 101010 such targets in a row. Assuming that Brandon is equally likely to hit each of the 101010 targets, what is the probability that he will hit at least one of them?
Round your answer to the nearest hundredth.
P(\text{at least one hit})=P(at least one hit)=P, left parenthesis, start text, a, t, space, l, e, a, s, t, space, o, n, e, space, h, i, t, end text, right parenthesis, equals

rounding to the nearest thousandth would be 452,000

answer: b

step-by-step explanation: im sorry bro bro but thats not a eqation the human mind can answer and plus im a devil

unless you made a typo, the answers are both a and c.

step-by-step explanation:

1.5/3 is .5 whereas 3/9 is .3333333 not proportional

22/33 is .66666 and 4/6 is also .66666 proportional

2/4 is .5 whereas 142/213 is .66666 not proportional

14/7 is 2 and 7/3.5 is also 2 proportional

you could've also checked it by doing this simple division:

if the larger fraction divides with the smaller fraction to equal 1, it is proportional. so let me show you what i mean:

when i divide 22/33 by 4/6 i get 1, so we know it is proportional, and it is the same with 14/7 and 7/3.5. now if i divide 3/9 by 1.5/3 i get .66666 so therefore we know it is not proportional.

there are many ways to do this so i wanted to show you some possible ways.