What is the least natural number that is greater than 10 and has a remainder of 5 when divided by 6, has a remainder of 5 when divided by 9, and has a remainder of 5 when divided by 12?

41

Step-by-step explanation:

I am essentially going through every multiply of 12 and then adding 5 to it, because we are using the rule that it should have a remainder of 5. It should also be a remainder of 5 if divided by 6 and 9 as well.

12 + 5 = 17

17/6 = 2 R 5

17/9 = 1 R 8

24 + 5 = 29

29/6 = 4 R 5

29/ 9 = 3 R 2

36 + 9 = 41

41/6 = 6 R 5

41/9 = 4 R 5

Hence, the number is 41

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-Chetan K

Step-by-step explanation6:

rx and sx

step-by-step explanation: