Can someone help me with this please?

Solution given:

<J=90°[tangent to the circle is perpendicular to radius]

In right angled triangle ∆KJL

base[b]=10

hypotenuse [h]=x+10

perpendicular [p]=24

by using Pythagoras law

p²+b²=h²

24²+10²=(x+10)²

(x+10)²=676

x+10=√676

x=26-10

x=16

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation: