A water tank is shaped like the cone shown here. How much water can the tank​ hold? Use 3.14 for . If water is drained from the tank to fill smaller tanks that each hold 200 m of​ wat

Question:A water tank is shaped like the cone shown here. How much water can the tank​ hold? Use 3.14 for . If water is drained from the tank to fill smaller tanks that each hold 200 m³ of​ water, how many smaller tanks can it fill

Amount of water = 871.87 in³

Number of tanks = 4 tanks

Step-by-step explanation:

Applying,

V = 1/3πr²h........... Equation 1.

Where V = volume of the tank, h = height, r = radius.

From the diagram attached,

Given: h = 17 m, r = 7 m.

Substitute these values into equation 1

V = 1/3(17)(7²)(3.14)

V = 871.87 m³.

Hence the amount of water the tank can hold is 871.87 m³

If the water is drained to a tank of 200 m³,

The number of tanks it can fill is = 871.87/200 = 4 tanks.

answer: it actually depends on which is the independent variable and which is the dependent variable. let us say we're looking at a linear equation. y=2x+3. we theoretically could switch the equation to be x=(y-3)/2 and it would be the same line. so either a causes b or it can be that b causes a. so technically the answer is false

step-by-step explanation:

third choice down

step-by-step explanation:

the first inequality is based on the number of adults and campers, and the second inequality is based on the cost of feeding both the adult and the camper.

we know that there is room for 525 people max.   it's ok to have less than 525, but it's not ok to have more than 525, so the inequality is less than or equal to.   the number combination of adults (x) and campers (y) cannot exceed this 525 max.   therefore:

x + y ≤ 525

now we talk about cost.   it costs $9 to feed one adult, so depending upon the number of adults you have (x) depends upon how much it will cost to feed that number of adults.   same with the campers, who cost $5 to feed.   the adults can be represented by 9x and the campers can be represented by 5y.   since the budget cannot exceed 1,200, the second inequality is:

9x + 5y ≤ 1200