The base of an isosceles triangle is 43m The perimeter of the triangle is 4215 cm what is the lenght of either of the remaining equal sides​

Let the length of equal sides be x cm. Perimeter = x cm + x cm + Base = 4 2/15 cm 2x + 4/3 = 62/15 On transposing 4/3 to R.H.S, we obtain 2x = 62/15 - 4/3 2x = 62 - 4 x 5/15 = 62 - 20/15 2x = 42/15 On dividing both sides by 2, we obtain 2x/2 = 42/15 x1/2 x = 7/5 = 1 2/5 Therefore, the length of equal sides is 1 2/5 c m.

addition

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