Lus Find the expected value of a
random variable x having the
following probability distribution.
5
1
0
1
8
Probability
12
16
U22
112
1
2

Well formatted version of question:

Find the expected value of a random variable x having the following probability distribution.

x (-5,-1,0,1,5,8)

Probability (.12, .16, .28, .22, .12, .1)

0.86

Step-by-step explanation:

The expected value E(X) is calculated as :

E(X) = Σ(x * p(x))

(-5)(0.12) + (-1)(0.16) + (0)(0.28) + 1(0.22) + 5(0.12) + 8(0.10)

-0.6 + -0.16 + 0 + 0.22 + 0.6 + 0.8

= 0.86

answer: about 22.67

step-by-step explanation:

answer: the proof is mentioned below.

step-by-step explanation:

since, given:   lines bc = ef

prove:   lines ac > ef

          statements                                           reason

1. bc=ef                                           1. given

2. ac= ab+bc                                 2. because b is the point between the  

                                                            line segment ac

3.   ac > bc                                       3. because if a line segment is equal to

                                                          the sum of two line segments then it is

                                                          always greater then each of these

                                                          individual line segments

4. ac > ef                                         4. by equality property.