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Mathematics, 16.05.2021 06:20 baches

Tanθ=

a. 1 - cot^2 θ
b. 1/cot θ
c. 1 + sec^2 θ

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Answers: 2

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Tanθ=

a. 1 - cot^2 θ
b. 1/cot θ
c. 1 + sec^2 θ...
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