Estimate 11.14+9.543 by first rounding each number to the nearest tenth.

HELP PLSZZ

To round each number to the nearest tenth, we have to look at the second digit after the decimal point, the hundredths. We look at tenths to round whole numbers, hundredths to round tenths, thousandths to round hundredths, etc. If the digit is 4 or below, then we would round down. If the digit is 5 or up, we would round up.

11.14

The digit is below 5, so we round down to 11.1.

9.543

The digit is also below 5, so we round down to 9.5.

Henceforth, adding these two numbers, we can conclude that an accurate estimation of the sum is 11.1 + 9.5, or 20.6.

If we wanted to round this answer further, we would use the same rounding rule. 20.6, where the tenths place digit, 6, is above 5, would be rounded up to 21.

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.