Which is the equation of a parabola with vertex (0, 0), that opens to the left and has a focal width of 12?
a. y2 = 12x
b. y2 = -12x
c. x = 12y
d. x = -12y

Step-by-step explanation:

I'm going to guess that the square  exponents are on the top y's   only?   then answer b) looks good

b. y^2 = -12x

Step-by-step explanation:

The general form for  the given parabola is y^2 = -4ax where the focus is at (-a, 0). The focal width is 4a which in this case = 12.

answer 1 : option "c"

answer 2 : option "d"

answer 3 : option "b"

answer 4 : option "d"

answer 5 : option "b"

answer 6 : option "a"

answer 7 : option "c"

answer 8 : option "d"

answer 9 : option "c"

answer 10 : option "d"

answer 11 : option "c"

answer 12 option "b"

answer 13 option "c"

answer 14 option "c"

answer 15 option "d"

answer 16 option "a"

answer 17 option "b"

answer 18 option "c"

answer 19 option "a"

answer 20 option "a"

answer 21 option "c"

d

after 1 year: 221 deer

step-by-step explanation:

30% of 170 is 51. 170+51=221