Please help! It would be very much appreciated :)

x=6/cos 45=6√2

x=6√2

tan 45=y/6

y=tan45 ×6

y=6

2.

sin 60=y/10

y=sin60×10

y=5√3

again

Cos 60=x/10

x=½×10

x=5

3.

Sin 45=x/5

x=1/√2×5 or

x=5√2/2

again

y=5√2/2 or 5/√2[base angle of right angled isosceles triangle]

4.

Sin 30=8/x

½×x=8

x=8*2

x=16

again

cos 30= y/x

√3/2×16=y

y=8√3

5.

sin 60=7/x

x=7/[√3/2]

x=14/√3 or 14√3/3

again

cos 60=y/x

½×14√3/3=y

7√3/2=y

y=7√3/2

Note:

Sin angle =perpendicular/hypotenuse

Cos angle =base/hypotenuse

Tan angle =perpendicular /base

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes

x/3-10=8

x/3=18

x=48